1.2x^2-3.6x+1=0

Solution for 1.2x^2-3.6x+1=0 equation:

1.2x^2-3.6x+1=0

a = 1.2; b = -3.6; c = +1;
Δ = b2-4ac
Δ = -3.62-4·1.2·1
Δ = 8.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.6)-\sqrt{8.16}}{2*1.2}=\frac{3.6-\sqrt{8.16}}{2.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.6)+\sqrt{8.16}}{2*1.2}=\frac{3.6+\sqrt{8.16}}{2.4}
$